七年级下册数学 期中复习(8)2016年4月

1、若\(\left( {m + 58} \right)2 = 654483\),则\(\left( {m + 48} \right)\left( {m + 68} \right) = \)        .

2、\({\left( { – 2{a^2}} \right)^3} \times {\left( { – a} \right)^2} \div {\left( { – 4{a^4}} \right)^2} = \)        .

3、已知\({a^{3m}} = 3\),\({a^n} = 9\),则\({a^{3m – n}} = \)        .

4、若\(a – b = 3\),则\({\left[ {{{\left( {a – b} \right)}^2}} \right]^3} \cdot {\left[ {{{\left( {b – a} \right)}^3}} \right]^2} = \)        (用幂的形式表示).

5、若\(\left| x \right| = {\left( {x – 1} \right)^0}\),则\(x = \)           .

6、\({x^2} + 6xy + \begin{array}{*{20}{c}} {}&{} \end{array} = {\left( {\begin{array}{*{20}{c}} {}&{} \end{array} + \begin{array}{*{20}{c}} {}&{} \end{array}} \right)^2}\)

7、\({x^{2n – 1}} \div \left( {\begin{array}{*{20}{c}} {}&{} \end{array}} \right) = {x^{n + 2}}\)(\(n\)是整数)

8、计算:\({\left( { – 0.25} \right)^{11}} \times {\left( { – 4} \right)^{12}} = \)        .

9、观察下列等式:\[\begin{array}{l} {2^0} + {2^1} = 1 \times \left( {1 + 2} \right) = 1 \times 3\\ {2^1} + {2^2} = 2 \times \left( {1 + 2} \right) = 2 \times 3\\ {2^2} + {2^3} = 4 \times \left( {1 + 2} \right) = 4 \times 3 \end{array}\]

……

依据你所发现的规律,请你写出第\(n\)个等式:        .

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